Option 3 : 6 L, 6 L

**Given∶ **

1st glass of mocktail contains 25% champagne and 75% beer.

2nd glass of mocktail contains 50% champagne and 50% beer.

Resulting ratio = 3 ∶ 5

Final quantity of beer is 12 liters.

**Formula Used∶**

**Calculation∶**

Amount of beer in x liters of the 1st glass = 0.75 x

Amount of champagne in x liters of the 1st glass = 0.25 x

Also, amount of beer in (12 - x) liters of the 2nd glass = 0.5 ( 12 - x)

Amount of champagne in (12 - x) liters of the 2nd glass = 0.5 ( 12 - x)

So, Ratio of champagne to milk,

⇒ [0.25x + 0.5(12 -x) ∶ [0.75x + 0.5 (12 - x)] = 3 ∶ 5

⇒ [0.25x + 6 - 0.5x] / [ 0.75x + 0.6 - 0.5x] = 3/5

⇒ [6 - 0.25x] / [ 0.25 x + 6] = 3/5

⇒ 30 - 1.25 x = 0.75 x + 18

⇒ 2x = 12

⇒ x = 6

Thus, x = 6 L

⇒ 12 - x = 12 - 6 = 6

**∴ Quantity of champagne from each glass should be 6 liters. The correct option is (3).**